Optimal. Leaf size=210 \[ -\frac{512 b^3 \sqrt{a+b x} (4 A b-3 a B)}{63 a^7 \sqrt{x}}+\frac{256 b^2 \sqrt{a+b x} (4 A b-3 a B)}{63 a^6 x^{3/2}}-\frac{64 b \sqrt{a+b x} (4 A b-3 a B)}{21 a^5 x^{5/2}}+\frac{160 \sqrt{a+b x} (4 A b-3 a B)}{63 a^4 x^{7/2}}-\frac{20 (4 A b-3 a B)}{9 a^3 x^{7/2} \sqrt{a+b x}}-\frac{2 (4 A b-3 a B)}{9 a^2 x^{7/2} (a+b x)^{3/2}}-\frac{2 A}{9 a x^{9/2} (a+b x)^{3/2}} \]
[Out]
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Rubi [A] time = 0.252535, antiderivative size = 210, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 3, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15 \[ -\frac{512 b^3 \sqrt{a+b x} (4 A b-3 a B)}{63 a^7 \sqrt{x}}+\frac{256 b^2 \sqrt{a+b x} (4 A b-3 a B)}{63 a^6 x^{3/2}}-\frac{64 b \sqrt{a+b x} (4 A b-3 a B)}{21 a^5 x^{5/2}}+\frac{160 \sqrt{a+b x} (4 A b-3 a B)}{63 a^4 x^{7/2}}-\frac{20 (4 A b-3 a B)}{9 a^3 x^{7/2} \sqrt{a+b x}}-\frac{2 (4 A b-3 a B)}{9 a^2 x^{7/2} (a+b x)^{3/2}}-\frac{2 A}{9 a x^{9/2} (a+b x)^{3/2}} \]
Antiderivative was successfully verified.
[In] Int[(A + B*x)/(x^(11/2)*(a + b*x)^(5/2)),x]
[Out]
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Rubi in Sympy [A] time = 24.6152, size = 207, normalized size = 0.99 \[ - \frac{2 A}{9 a x^{\frac{9}{2}} \left (a + b x\right )^{\frac{3}{2}}} - \frac{2 \left (4 A b - 3 B a\right )}{9 a^{2} x^{\frac{7}{2}} \left (a + b x\right )^{\frac{3}{2}}} - \frac{20 \left (4 A b - 3 B a\right )}{9 a^{3} x^{\frac{7}{2}} \sqrt{a + b x}} + \frac{160 \sqrt{a + b x} \left (4 A b - 3 B a\right )}{63 a^{4} x^{\frac{7}{2}}} - \frac{64 b \sqrt{a + b x} \left (4 A b - 3 B a\right )}{21 a^{5} x^{\frac{5}{2}}} + \frac{256 b^{2} \sqrt{a + b x} \left (4 A b - 3 B a\right )}{63 a^{6} x^{\frac{3}{2}}} - \frac{512 b^{3} \sqrt{a + b x} \left (4 A b - 3 B a\right )}{63 a^{7} \sqrt{x}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)/x**(11/2)/(b*x+a)**(5/2),x)
[Out]
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Mathematica [A] time = 0.17499, size = 127, normalized size = 0.6 \[ -\frac{2 \left (a^6 (7 A+9 B x)-6 a^5 b x (2 A+3 B x)+24 a^4 b^2 x^2 (A+2 B x)-32 a^3 b^3 x^3 (2 A+9 B x)+384 a^2 b^4 x^4 (A-3 B x)-768 a b^5 x^5 (B x-2 A)+1024 A b^6 x^6\right )}{63 a^7 x^{9/2} (a+b x)^{3/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(A + B*x)/(x^(11/2)*(a + b*x)^(5/2)),x]
[Out]
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Maple [A] time = 0.009, size = 149, normalized size = 0.7 \[ -{\frac{2048\,A{b}^{6}{x}^{6}-1536\,Ba{b}^{5}{x}^{6}+3072\,Aa{b}^{5}{x}^{5}-2304\,B{a}^{2}{b}^{4}{x}^{5}+768\,A{a}^{2}{b}^{4}{x}^{4}-576\,B{a}^{3}{b}^{3}{x}^{4}-128\,A{a}^{3}{b}^{3}{x}^{3}+96\,B{a}^{4}{b}^{2}{x}^{3}+48\,A{a}^{4}{b}^{2}{x}^{2}-36\,B{a}^{5}b{x}^{2}-24\,A{a}^{5}bx+18\,B{a}^{6}x+14\,A{a}^{6}}{63\,{a}^{7}}{x}^{-{\frac{9}{2}}} \left ( bx+a \right ) ^{-{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)/x^(11/2)/(b*x+a)^(5/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^(5/2)*x^(11/2)),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.238075, size = 223, normalized size = 1.06 \[ -\frac{2 \,{\left (7 \, A a^{6} - 256 \,{\left (3 \, B a b^{5} - 4 \, A b^{6}\right )} x^{6} - 384 \,{\left (3 \, B a^{2} b^{4} - 4 \, A a b^{5}\right )} x^{5} - 96 \,{\left (3 \, B a^{3} b^{3} - 4 \, A a^{2} b^{4}\right )} x^{4} + 16 \,{\left (3 \, B a^{4} b^{2} - 4 \, A a^{3} b^{3}\right )} x^{3} - 6 \,{\left (3 \, B a^{5} b - 4 \, A a^{4} b^{2}\right )} x^{2} + 3 \,{\left (3 \, B a^{6} - 4 \, A a^{5} b\right )} x\right )}}{63 \,{\left (a^{7} b x^{5} + a^{8} x^{4}\right )} \sqrt{b x + a} \sqrt{x}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^(5/2)*x^(11/2)),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)/x**(11/2)/(b*x+a)**(5/2),x)
[Out]
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GIAC/XCAS [A] time = 0.337634, size = 537, normalized size = 2.56 \[ -\frac{{\left ({\left ({\left (b x + a\right )}{\left ({\left (b x + a\right )}{\left (\frac{{\left (474 \, B a^{19} b^{13} - 667 \, A a^{18} b^{14}\right )}{\left (b x + a\right )}}{a^{5} b^{15}} - \frac{9 \,{\left (223 \, B a^{20} b^{13} - 316 \, A a^{19} b^{14}\right )}}{a^{5} b^{15}}\right )} + \frac{63 \,{\left (51 \, B a^{21} b^{13} - 73 \, A a^{20} b^{14}\right )}}{a^{5} b^{15}}\right )} - \frac{210 \,{\left (11 \, B a^{22} b^{13} - 16 \, A a^{21} b^{14}\right )}}{a^{5} b^{15}}\right )}{\left (b x + a\right )} + \frac{315 \,{\left (2 \, B a^{23} b^{13} - 3 \, A a^{22} b^{14}\right )}}{a^{5} b^{15}}\right )} \sqrt{b x + a}}{64512 \,{\left ({\left (b x + a\right )} b - a b\right )}^{\frac{9}{2}}} + \frac{4 \,{\left (12 \, B a{\left (\sqrt{b x + a} \sqrt{b} - \sqrt{{\left (b x + a\right )} b - a b}\right )}^{4} b^{\frac{11}{2}} + 30 \, B a^{2}{\left (\sqrt{b x + a} \sqrt{b} - \sqrt{{\left (b x + a\right )} b - a b}\right )}^{2} b^{\frac{13}{2}} - 15 \, A{\left (\sqrt{b x + a} \sqrt{b} - \sqrt{{\left (b x + a\right )} b - a b}\right )}^{4} b^{\frac{13}{2}} + 14 \, B a^{3} b^{\frac{15}{2}} - 36 \, A a{\left (\sqrt{b x + a} \sqrt{b} - \sqrt{{\left (b x + a\right )} b - a b}\right )}^{2} b^{\frac{15}{2}} - 17 \, A a^{2} b^{\frac{17}{2}}\right )}}{3 \,{\left ({\left (\sqrt{b x + a} \sqrt{b} - \sqrt{{\left (b x + a\right )} b - a b}\right )}^{2} + a b\right )}^{3} a^{6}{\left | b \right |}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^(5/2)*x^(11/2)),x, algorithm="giac")
[Out]